Integrand size = 35, antiderivative size = 166 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=-\frac {2521723 (1+5 x) \sqrt {3+2 x+5 x^2}}{1250000}+\frac {198439 \left (3+2 x+5 x^2\right )^{3/2}}{750000}+\frac {1781669 x \left (3+2 x+5 x^2\right )^{3/2}}{250000}-\frac {77509 x^2 \left (3+2 x+5 x^2\right )^{3/2}}{25000}-\frac {25277 x^3 \left (3+2 x+5 x^2\right )^{3/2}}{3000}+\frac {989}{200} x^4 \left (3+2 x+5 x^2\right )^{3/2}+\frac {49}{40} x^5 \left (3+2 x+5 x^2\right )^{3/2}-\frac {17652061 \text {arcsinh}\left (\frac {1+5 x}{\sqrt {14}}\right )}{625000 \sqrt {5}} \]
198439/750000*(5*x^2+2*x+3)^(3/2)+1781669/250000*x*(5*x^2+2*x+3)^(3/2)-775 09/25000*x^2*(5*x^2+2*x+3)^(3/2)-25277/3000*x^3*(5*x^2+2*x+3)^(3/2)+989/20 0*x^4*(5*x^2+2*x+3)^(3/2)+49/40*x^5*(5*x^2+2*x+3)^(3/2)-17652061/3125000*a rcsinh(1/14*(1+5*x)*14^(1/2))*5^(1/2)-2521723/1250000*(1+5*x)*(5*x^2+2*x+3 )^(1/2)
Time = 0.48 (sec) , antiderivative size = 89, normalized size of antiderivative = 0.54 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\frac {\sqrt {3+2 x+5 x^2} \left (-4588584+44333650 x+23531995 x^2+15583725 x^3-65693000 x^4-107112500 x^5+101906250 x^6+22968750 x^7\right )}{3750000}+\frac {17652061 \log \left (-1-5 x+\sqrt {5} \sqrt {3+2 x+5 x^2}\right )}{625000 \sqrt {5}} \]
(Sqrt[3 + 2*x + 5*x^2]*(-4588584 + 44333650*x + 23531995*x^2 + 15583725*x^ 3 - 65693000*x^4 - 107112500*x^5 + 101906250*x^6 + 22968750*x^7))/3750000 + (17652061*Log[-1 - 5*x + Sqrt[5]*Sqrt[3 + 2*x + 5*x^2]])/(625000*Sqrt[5] )
Time = 0.58 (sec) , antiderivative size = 197, normalized size of antiderivative = 1.19, number of steps used = 14, number of rules used = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.371, Rules used = {2192, 2192, 27, 2192, 27, 2192, 27, 2192, 25, 1160, 1087, 1090, 222}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
\(\displaystyle \int \left (-7 x^2+4 x+1\right )^2 \left (x^2+5 x+2\right ) \sqrt {5 x^2+2 x+3} \, dx\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {1}{40} \int \sqrt {5 x^2+2 x+3} \left (6923 x^5-7935 x^4-3760 x^3+1800 x^2+840 x+80\right )dx+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {1}{40} \left (\frac {1}{35} \int 14 \sqrt {5 x^2+2 x+3} \left (-25277 x^4-15334 x^3+4500 x^2+2100 x+200\right )dx+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \int \sqrt {5 x^2+2 x+3} \left (-25277 x^4-15334 x^3+4500 x^2+2100 x+200\right )dx+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{30} \int 3 \sqrt {5 x^2+2 x+3} \left (-77509 x^3+120831 x^2+21000 x+2000\right )dx-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \int \sqrt {5 x^2+2 x+3} \left (-77509 x^3+120831 x^2+21000 x+2000\right )dx-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {1}{25} \int 2 \sqrt {5 x^2+2 x+3} \left (1781669 x^2+495027 x+25000\right )dx-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 27 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \int \sqrt {5 x^2+2 x+3} \left (1781669 x^2+495027 x+25000\right )dx-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 2192 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1}{20} \int -\left ((4845007-992195 x) \sqrt {5 x^2+2 x+3}\right )dx+\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 25 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}-\frac {1}{20} \int (4845007-992195 x) \sqrt {5 x^2+2 x+3}dx\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 1160 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1}{20} \left (\frac {198439}{3} \left (5 x^2+2 x+3\right )^{3/2}-5043446 \int \sqrt {5 x^2+2 x+3}dx\right )+\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 1087 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1}{20} \left (\frac {198439}{3} \left (5 x^2+2 x+3\right )^{3/2}-5043446 \left (\frac {7}{5} \int \frac {1}{\sqrt {5 x^2+2 x+3}}dx+\frac {1}{10} \sqrt {5 x^2+2 x+3} (5 x+1)\right )\right )+\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 1090 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1}{20} \left (\frac {198439}{3} \left (5 x^2+2 x+3\right )^{3/2}-5043446 \left (\frac {1}{10} \sqrt {\frac {7}{10}} \int \frac {1}{\sqrt {\frac {1}{56} (10 x+2)^2+1}}d(10 x+2)+\frac {1}{10} \sqrt {5 x^2+2 x+3} (5 x+1)\right )\right )+\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
\(\Big \downarrow \) 222 |
\(\displaystyle \frac {1}{40} \left (\frac {2}{5} \left (\frac {1}{10} \left (\frac {2}{25} \left (\frac {1}{20} \left (\frac {198439}{3} \left (5 x^2+2 x+3\right )^{3/2}-5043446 \left (\frac {7 \text {arcsinh}\left (\frac {10 x+2}{2 \sqrt {14}}\right )}{5 \sqrt {5}}+\frac {1}{10} \sqrt {5 x^2+2 x+3} (5 x+1)\right )\right )+\frac {1781669}{20} x \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {77509}{25} x^2 \left (5 x^2+2 x+3\right )^{3/2}\right )-\frac {25277}{30} x^3 \left (5 x^2+2 x+3\right )^{3/2}\right )+\frac {989}{5} \left (5 x^2+2 x+3\right )^{3/2} x^4\right )+\frac {49}{40} \left (5 x^2+2 x+3\right )^{3/2} x^5\) |
(49*x^5*(3 + 2*x + 5*x^2)^(3/2))/40 + ((989*x^4*(3 + 2*x + 5*x^2)^(3/2))/5 + (2*((-25277*x^3*(3 + 2*x + 5*x^2)^(3/2))/30 + ((-77509*x^2*(3 + 2*x + 5 *x^2)^(3/2))/25 + (2*((1781669*x*(3 + 2*x + 5*x^2)^(3/2))/20 + ((198439*(3 + 2*x + 5*x^2)^(3/2))/3 - 5043446*(((1 + 5*x)*Sqrt[3 + 2*x + 5*x^2])/10 + (7*ArcSinh[(2 + 10*x)/(2*Sqrt[14])])/(5*Sqrt[5])))/20))/25)/10))/5)/40
3.4.75.3.1 Defintions of rubi rules used
Int[(a_)*(Fx_), x_Symbol] :> Simp[a Int[Fx, x], x] /; FreeQ[a, x] && !Ma tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSinh[Rt[b, 2]*(x/Sqrt [a])]/Rt[b, 2], x] /; FreeQ[{a, b}, x] && GtQ[a, 0] && PosQ[b]
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[(b + 2*c*x) *((a + b*x + c*x^2)^p/(2*c*(2*p + 1))), x] - Simp[p*((b^2 - 4*a*c)/(2*c*(2* p + 1))) Int[(a + b*x + c*x^2)^(p - 1), x], x] /; FreeQ[{a, b, c}, x] && GtQ[p, 0] && (IntegerQ[4*p] || IntegerQ[3*p])
Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> Simp[1/(2*c*(-4* (c/(b^2 - 4*a*c)))^p) Subst[Int[Simp[1 - x^2/(b^2 - 4*a*c), x]^p, x], x, b + 2*c*x], x] /; FreeQ[{a, b, c, p}, x] && GtQ[4*a - b^2/c, 0]
Int[((d_.) + (e_.)*(x_))*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol ] :> Simp[e*((a + b*x + c*x^2)^(p + 1)/(2*c*(p + 1))), x] + Simp[(2*c*d - b *e)/(2*c) Int[(a + b*x + c*x^2)^p, x], x] /; FreeQ[{a, b, c, d, e, p}, x] && NeQ[p, -1]
Int[(Pq_)*((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(p_), x_Symbol] :> With[{q = Expon[Pq, x], e = Coeff[Pq, x, Expon[Pq, x]]}, Simp[e*x^(q - 1)*((a + b*x + c*x^2)^(p + 1)/(c*(q + 2*p + 1))), x] + Simp[1/(c*(q + 2*p + 1)) Int[(a + b*x + c*x^2)^p*ExpandToSum[c*(q + 2*p + 1)*Pq - a*e*(q - 1)*x^(q - 2) - b *e*(q + p)*x^(q - 1) - c*e*(q + 2*p + 1)*x^q, x], x], x]] /; FreeQ[{a, b, c , p}, x] && PolyQ[Pq, x] && NeQ[b^2 - 4*a*c, 0] && !LeQ[p, -1]
Time = 0.28 (sec) , antiderivative size = 65, normalized size of antiderivative = 0.39
method | result | size |
risch | \(\frac {\left (22968750 x^{7}+101906250 x^{6}-107112500 x^{5}-65693000 x^{4}+15583725 x^{3}+23531995 x^{2}+44333650 x -4588584\right ) \sqrt {5 x^{2}+2 x +3}}{3750000}-\frac {17652061 \sqrt {5}\, \operatorname {arcsinh}\left (\frac {5 \sqrt {14}\, \left (x +\frac {1}{5}\right )}{14}\right )}{3125000}\) | \(65\) |
trager | \(\left (\frac {49}{8} x^{7}+\frac {1087}{40} x^{6}-\frac {8569}{300} x^{5}-\frac {65693}{3750} x^{4}+\frac {207783}{50000} x^{3}+\frac {4706399}{750000} x^{2}+\frac {886673}{75000} x -\frac {191191}{156250}\right ) \sqrt {5 x^{2}+2 x +3}+\frac {17652061 \operatorname {RootOf}\left (\textit {\_Z}^{2}-5\right ) \ln \left (-5 \operatorname {RootOf}\left (\textit {\_Z}^{2}-5\right ) x +5 \sqrt {5 x^{2}+2 x +3}-\operatorname {RootOf}\left (\textit {\_Z}^{2}-5\right )\right )}{3125000}\) | \(91\) |
default | \(-\frac {2521723 \left (10 x +2\right ) \sqrt {5 x^{2}+2 x +3}}{2500000}-\frac {17652061 \sqrt {5}\, \operatorname {arcsinh}\left (\frac {5 \sqrt {14}\, \left (x +\frac {1}{5}\right )}{14}\right )}{3125000}+\frac {198439 \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{750000}+\frac {49 x^{5} \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{40}+\frac {989 x^{4} \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{200}-\frac {25277 x^{3} \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{3000}-\frac {77509 x^{2} \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{25000}+\frac {1781669 x \left (5 x^{2}+2 x +3\right )^{\frac {3}{2}}}{250000}\) | \(132\) |
1/3750000*(22968750*x^7+101906250*x^6-107112500*x^5-65693000*x^4+15583725* x^3+23531995*x^2+44333650*x-4588584)*(5*x^2+2*x+3)^(1/2)-17652061/3125000* 5^(1/2)*arcsinh(5/14*14^(1/2)*(x+1/5))
Time = 0.27 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.52 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\frac {1}{3750000} \, {\left (22968750 \, x^{7} + 101906250 \, x^{6} - 107112500 \, x^{5} - 65693000 \, x^{4} + 15583725 \, x^{3} + 23531995 \, x^{2} + 44333650 \, x - 4588584\right )} \sqrt {5 \, x^{2} + 2 \, x + 3} + \frac {17652061}{6250000} \, \sqrt {5} \log \left (\sqrt {5} \sqrt {5 \, x^{2} + 2 \, x + 3} {\left (5 \, x + 1\right )} - 25 \, x^{2} - 10 \, x - 8\right ) \]
1/3750000*(22968750*x^7 + 101906250*x^6 - 107112500*x^5 - 65693000*x^4 + 1 5583725*x^3 + 23531995*x^2 + 44333650*x - 4588584)*sqrt(5*x^2 + 2*x + 3) + 17652061/6250000*sqrt(5)*log(sqrt(5)*sqrt(5*x^2 + 2*x + 3)*(5*x + 1) - 25 *x^2 - 10*x - 8)
Time = 0.43 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.51 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\sqrt {5 x^{2} + 2 x + 3} \cdot \left (\frac {49 x^{7}}{8} + \frac {1087 x^{6}}{40} - \frac {8569 x^{5}}{300} - \frac {65693 x^{4}}{3750} + \frac {207783 x^{3}}{50000} + \frac {4706399 x^{2}}{750000} + \frac {886673 x}{75000} - \frac {191191}{156250}\right ) - \frac {17652061 \sqrt {5} \operatorname {asinh}{\left (\frac {5 \sqrt {14} \left (x + \frac {1}{5}\right )}{14} \right )}}{3125000} \]
sqrt(5*x**2 + 2*x + 3)*(49*x**7/8 + 1087*x**6/40 - 8569*x**5/300 - 65693*x **4/3750 + 207783*x**3/50000 + 4706399*x**2/750000 + 886673*x/75000 - 1911 91/156250) - 17652061*sqrt(5)*asinh(5*sqrt(14)*(x + 1/5)/14)/3125000
Time = 0.29 (sec) , antiderivative size = 143, normalized size of antiderivative = 0.86 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\frac {49}{40} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} x^{5} + \frac {989}{200} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} x^{4} - \frac {25277}{3000} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} x^{3} - \frac {77509}{25000} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} x^{2} + \frac {1781669}{250000} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} x + \frac {198439}{750000} \, {\left (5 \, x^{2} + 2 \, x + 3\right )}^{\frac {3}{2}} - \frac {2521723}{250000} \, \sqrt {5 \, x^{2} + 2 \, x + 3} x - \frac {17652061}{3125000} \, \sqrt {5} \operatorname {arsinh}\left (\frac {1}{14} \, \sqrt {14} {\left (5 \, x + 1\right )}\right ) - \frac {2521723}{1250000} \, \sqrt {5 \, x^{2} + 2 \, x + 3} \]
49/40*(5*x^2 + 2*x + 3)^(3/2)*x^5 + 989/200*(5*x^2 + 2*x + 3)^(3/2)*x^4 - 25277/3000*(5*x^2 + 2*x + 3)^(3/2)*x^3 - 77509/25000*(5*x^2 + 2*x + 3)^(3/ 2)*x^2 + 1781669/250000*(5*x^2 + 2*x + 3)^(3/2)*x + 198439/750000*(5*x^2 + 2*x + 3)^(3/2) - 2521723/250000*sqrt(5*x^2 + 2*x + 3)*x - 17652061/312500 0*sqrt(5)*arcsinh(1/14*sqrt(14)*(5*x + 1)) - 2521723/1250000*sqrt(5*x^2 + 2*x + 3)
Time = 0.28 (sec) , antiderivative size = 82, normalized size of antiderivative = 0.49 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\frac {1}{3750000} \, {\left (5 \, {\left ({\left (5 \, {\left (10 \, {\left (25 \, {\left (15 \, {\left (245 \, x + 1087\right )} x - 17138\right )} x - 262772\right )} x + 623349\right )} x + 4706399\right )} x + 8866730\right )} x - 4588584\right )} \sqrt {5 \, x^{2} + 2 \, x + 3} + \frac {17652061}{3125000} \, \sqrt {5} \log \left (-\sqrt {5} {\left (\sqrt {5} x - \sqrt {5 \, x^{2} + 2 \, x + 3}\right )} - 1\right ) \]
1/3750000*(5*((5*(10*(25*(15*(245*x + 1087)*x - 17138)*x - 262772)*x + 623 349)*x + 4706399)*x + 8866730)*x - 4588584)*sqrt(5*x^2 + 2*x + 3) + 176520 61/3125000*sqrt(5)*log(-sqrt(5)*(sqrt(5)*x - sqrt(5*x^2 + 2*x + 3)) - 1)
Time = 15.04 (sec) , antiderivative size = 187, normalized size of antiderivative = 1.13 \[ \int \left (1+4 x-7 x^2\right )^2 \left (2+5 x+x^2\right ) \sqrt {3+2 x+5 x^2} \, dx=\frac {989\,x^4\,{\left (5\,x^2+2\,x+3\right )}^{3/2}}{200}-\frac {25277\,x^3\,{\left (5\,x^2+2\,x+3\right )}^{3/2}}{3000}-\frac {77509\,x^2\,{\left (5\,x^2+2\,x+3\right )}^{3/2}}{25000}+\frac {49\,x^5\,{\left (5\,x^2+2\,x+3\right )}^{3/2}}{40}-\frac {33915049\,\sqrt {5}\,\ln \left (\sqrt {5\,x^2+2\,x+3}+\frac {\sqrt {5}\,\left (5\,x+1\right )}{5}\right )}{6250000}-\frac {4845007\,\left (\frac {x}{2}+\frac {1}{10}\right )\,\sqrt {5\,x^2+2\,x+3}}{250000}+\frac {198439\,\sqrt {5\,x^2+2\,x+3}\,\left (200\,x^2+20\,x+108\right )}{30000000}+\frac {1781669\,x\,{\left (5\,x^2+2\,x+3\right )}^{3/2}}{250000}-\frac {1389073\,\sqrt {5}\,\ln \left (2\,\sqrt {5\,x^2+2\,x+3}+\frac {\sqrt {5}\,\left (10\,x+2\right )}{5}\right )}{6250000} \]
(989*x^4*(2*x + 5*x^2 + 3)^(3/2))/200 - (25277*x^3*(2*x + 5*x^2 + 3)^(3/2) )/3000 - (77509*x^2*(2*x + 5*x^2 + 3)^(3/2))/25000 + (49*x^5*(2*x + 5*x^2 + 3)^(3/2))/40 - (33915049*5^(1/2)*log((2*x + 5*x^2 + 3)^(1/2) + (5^(1/2)* (5*x + 1))/5))/6250000 - (4845007*(x/2 + 1/10)*(2*x + 5*x^2 + 3)^(1/2))/25 0000 + (198439*(2*x + 5*x^2 + 3)^(1/2)*(20*x + 200*x^2 + 108))/30000000 + (1781669*x*(2*x + 5*x^2 + 3)^(3/2))/250000 - (1389073*5^(1/2)*log(2*(2*x + 5*x^2 + 3)^(1/2) + (5^(1/2)*(10*x + 2))/5))/6250000